Difference between revisions of "2024 AMC 10B Problems/Problem 2"
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~Aray10 (Main Solution) and RULE101 (Modifications for certain China test papers) | ~Aray10 (Main Solution) and RULE101 (Modifications for certain China test papers) | ||
+ | ==Solution 1== | ||
+ | Factoring out <math>7!</math> gives <cmath>7!(10\cdot9\cdot8-1\cdot6!).</cmath> Since <math>10\cdot9\cdot8=6!=720</math>, the answer is <math>\boxed{\text{(B) }0}</math> ~Tacos_are_yummy_1 | ||
+ | |||
+ | [b][u]Remark[/b][/u] | ||
+ | Factoring <math>6!</math> also works, it just makes the expression in the parenthesis a little harder to compute. | ||
==Video Solution 1 by Pi Academy (Fast and Easy ⚡🚀)== | ==Video Solution 1 by Pi Academy (Fast and Easy ⚡🚀)== |
Revision as of 11:43, 14 November 2024
- The following problem is from both the 2024 AMC 10B #2 and 2024 AMC 12B #2, so both problems redirect to this page.
Contents
Problem
What is
Certain China testpapers:
What is
Solution 1
Therefore, the equation is equal to
Solution for certain China test papers:
~Aray10 (Main Solution) and RULE101 (Modifications for certain China test papers)
Solution 1
Factoring out gives Since , the answer is ~Tacos_are_yummy_1
[b][u]Remark[/b][/u] Factoring also works, it just makes the expression in the parenthesis a little harder to compute.
Video Solution 1 by Pi Academy (Fast and Easy ⚡🚀)
https://youtu.be/DIl3rLQQkQQ?feature=shared
~ Pi Academy
See also
2024 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2024 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.