Difference between revisions of "2024 AMC 10B Problems/Problem 1"
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==Problem== | ==Problem== | ||
| − | In a long line of people arranged left to right, the 1013th (1015th for some certain test papers) person from the left is also the 1010th person from the right. How many people are in line? | + | In a long line of people arranged left to right, the 1013th (1015th for some certain test papers in China) person from the left is also the 1010th person from the right. How many people are in line? |
<math>\textbf{(A) } 2021 \qquad\textbf{(B) } 2022 \qquad\textbf{(C) } 2023 \qquad\textbf{(D) } 2024 \qquad\textbf{(E) } 2025</math> | <math>\textbf{(A) } 2021 \qquad\textbf{(B) } 2022 \qquad\textbf{(C) } 2023 \qquad\textbf{(D) } 2024 \qquad\textbf{(E) } 2025</math> | ||
Revision as of 04:02, 14 November 2024
- The following problem is from both the 2024 AMC 10B #1 and 2024 AMC 12B #1, so both problems redirect to this page.
Problem
In a long line of people arranged left to right, the 1013th (1015th for some certain test papers in China) person from the left is also the 1010th person from the right. How many people are in line?
Solution 1
If the person is the 1013th (1015th) from the left, that means there is 1012 people to their left.
If the person is the 1010th from the right, that means there is 1009 people to their right.
Therefore, there are 
people in line.
~Aray10 and RULE101 (added different answers for certain test papers in China)
See also
| 2024 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2024 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by First Problem |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
