Difference between revisions of "1971 AHSME Problems/Problem 28"
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Revision as of 10:56, 7 August 2024
Problem
Nine lines parallel to the base of a triangle divide the other sides each into 
equal segments and the area into distinct parts.
If the area of the largest of these parts is 
, then the area of the original triangle is
Solution
![[asy] import geometry; point B = origin; point A = (3,5); point C = (7,0); triangle t = triangle(A,B,C); point D = B*9/10 + A/10; point E; // Defining point E pair[] e = intersectionpoints(parallel(D,line(B,C)),A--C); E = e[0]; // Triangle ABC and Parallel Segment draw(t); draw(D--E); // Point Labels dot(A); label("A",A,NW); dot(B); label("B",B,SW); dot(C); label("C",C,SE); dot(D); label("D",D,NW); dot(E); label("E",E,NE); [/asy]](http://latex.artofproblemsolving.com/a/2/c/a2c87b4feaafa663d4dcca308b1e3185ce737fa8.png)
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See Also
| 1971 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 27 |
Followed by Problem 29 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
