1960 AHSME Problems/Problem 3

Problem

Applied to a bill for $\textdollar{10,000}$ the difference between a discount of $40$ % and two successive discounts of $36$ % and $4$ %, expressed in dollars, is:

$\textbf{(A)}0\qquad \textbf{(B)}144\qquad \textbf{(C)}256\qquad \textbf{(D)}400\qquad \textbf{(E)}416$

Solution

Taking the discount of $40$ % means you're only paying $60$ % of the bill. That results in $10,000\cdot0.6=\textdollar{6,000}$ .

Likewise, taking two discounts of $36$ % and $4$ % means taking $64$ % of the original amount and then $96$ % of the result. That results in $10,000\cdot0.64\cdot0.96=\textdollar{6,144}$ .

Taking the difference results in $6,144-6,000=\textdollar{144}$ , or answer choice $\boxed{\textbf{(B)}}$ .

1960 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
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1960 AHSME Problems/Problem 3

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