1960 AHSME Problems/Problem 26
Problem
Find the set of -values satisfying the inequality
. [The symbol
means
if
is positive,
if
is negative,
if
is zero. The notation
means that a can have any value between
and
, excluding
and
. ]
Solutions
Solution 1
Break up the absolute value into two cases.
For the first case, let , so
is positive. That means (for
)
For the second case, let
, so
is negative. That means (for
)
Combine both cases to get , which is answer choice
.
Solution 2
Another way to solve this is to graph and
. The solution is the areas on the graph where the y-values of
are lower than
. From the graph,
, so the answer is
.
See Also
1960 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 25 |
Followed by Problem 27 | |
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All AHSME Problems and Solutions |