2001 OIM Problems/Problem 5

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Problem

On a $2000 \times 2001$ board the squares have coordinates $(x, y)$ with $x, y$ integers, $0 \le x le 1999$ and $0 \le y \le 2000$. A ship on the board moves as follows: Before each movement, the ship is in a position $(x, y)$ and has a speed $(h, v)$ where $h$ and $v$ are integers. The ship chooses a new speed $(h',b'} such that$ (Error compiling LaTeX. Unknown error_msg)h'-h$be equal to$−1, 0$or$1$and$v'-v$be equal to$−1, 0$or$1$. The new position of the ship will be$(x',y')$where$x'$is the reminder of the division of$x+h'$by 2000, and$y'$is the reminder of the division of$y+v'$by 2001.  There are two ships on the board: the Martian one and the Earth one that wants to catch the Martian one. Initially each ship is on a square on the board and has speed$(0, 0)$. First moves Earth ship and continue moving alternately. Is there a strategy that always allows the Earth ship to catch the Martian ship, whatever the initial positions are?

Note: the Earth ship, which always sees the Martian, catches the Martian if after one of its movement falls at the same position as the Martian.


~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

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See also