1960 AHSME Problems/Problem 34

Problem 34

Two swimmers, at opposite ends of a $90$ -foot pool, start to swim the length of the pool, one at the rate of $3$ feet per second, the other at $2$ feet per second. They swim back and forth for $12$ minutes. Allowing no loss of times at the turns, find the number of times they pass each other.

$\textbf{(A)}\ 24\qquad \textbf{(B)}\ 21\qquad \textbf{(C)}\ 20\qquad \textbf{(D)}\ 19\qquad \textbf{(E)}\ 18$

Solution

First, note that it will take $30$ seconds for the first swimmer to reach the other side and $45$ seconds for the second swimmer to reach the other side. Also, note that after $180$ seconds (or $3$ minutes), both swimmers will complete an even number of laps, essentially returning to their starting point.

$[asy] draw((0,0)--(0,90),EndArrow); draw((0,0)--(90,0),EndArrow); [/asy]$

At this point, find the number of meeting points in the first $3$ minutes, then multiply by four to get the answer.

1960 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 33	Followed by Problem 35
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1960 AHSME Problems/Problem 34

Problem 34

Solution

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