2007 AMC 8 Problems/Problem 14
Problem
The base of isosceles 
is 
and its area is 
. What is the length of one
of the congruent sides?
Solution
The area of a triangle is shown by 1 half bh We set the base equal to 24 and the area equal to 60 and we get the height, or altitude, of the triangle to be 5 In this isosceles triangle, the height bisects the base a^2+b^2=c^2 we can solve for one of the legs of the triangle (it will be the the hypotenuse, 
).
a = 12 b = 5
c = 13
The answer is C:13
Video Solution by WhyMath
~savannahsolver
See Also
| 2007 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
