2007 AMC 8 Problems/Problem 17

Problem

A mixture of $30$ liters of paint is $25\%$ red tint, $30\%$ yellow tint and $45\%$ water. Five liters of yellow tint are added to the original mixture. What is the percent of yellow tint in the new mixture?

$\mathrm{(A)}\ 25 \qquad \mathrm{(B)}\ 35 \qquad \mathrm{(C)}\ 40 \qquad \mathrm{(D)}\ 45 \qquad \mathrm{(E)}\ 50$

Solution

Since $30\%$ of the original $30$ liters of paint was yellow, and $5$ liters of yellow paint were added to make the new mixture, there are $9+5=14$ liters of yellow tint in the new mixture. Since only $5$ liters of paint were added to the original $30$, there are a total of $35$ liters of paint in the new mixture. This gives $40\%$ of yellow tint in the new mixture, which is $\boxed{\textbf{(C) 40}}$.

Video Solution by WhyMath

https://youtu.be/5MfwBvLHUCw

~savannahsolver

Video Solution

https://youtu.be/StRqfN7yYE8 Soo, DRMS, NM

See Also

2007 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 16
Followed by
Problem 18
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png