Difference between revisions of "2007 AMC 8 Problems/Problem 4"

(Solution)
Line 11: Line 11:
 
Georgie can enter the haunted house through any of the six windows. Then, he can leave through any of the remaining five windows.
 
Georgie can enter the haunted house through any of the six windows. Then, he can leave through any of the remaining five windows.
  
So, Georgie has a total of <math>6 * 5</math> ways he can enter the house by one window and leave
+
So, Georgie has a total of <math>6 \cdot 5</math> ways he can enter the house by one window and leave
 
by a different window.
 
by a different window.
  

Revision as of 11:48, 5 November 2017

Problem

A haunted house has six windows. In how many ways can Georgie the Ghost enter the house by one window and leave by a different window?

$\mathrm{(A)}\ 12 \qquad\mathrm{(B)}\ 15 \qquad\mathrm{(C)}\ 18 \qquad\mathrm{(D)}\ 30 \qquad\mathrm{(E)}\ 36$

Solution

Georgie can enter the haunted house through any of the six windows. Then, he can leave through any of the remaining five windows.

So, Georgie has a total of $6 \cdot 5$ ways he can enter the house by one window and leave by a different window.

Therefore, we have $\boxed{\textbf{(D)}\ 30}$ ways.

See Also

2007 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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