Difference between revisions of "2025 AMC 8 Problems/Problem 4"
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− | Knowing that our first term is <math>100</math>, we have to add <math>7</math> to get to our | + | Knowing that our first term is <math>100</math>, we have to add <math>7</math> to get to our "0th term", <math>107</math>. To find the answer, we then multiply <math>10</math> by <math>7</math> and subtract that from our 0th term to get to our answer, which is <math>\boxed{\text{(B)\ 37}}</math>. |
~Kapurnicus | ~Kapurnicus |
Revision as of 20:09, 24 February 2025
Contents
- 1 Problem
- 2 Solution 1
- 3 Solution 2
- 4 Solution 3
- 5 Solution 4
- 6 Video Solution 1
- 7 Video Solution by SpreadTheMathLove
- 8 Video Solution 2 by Daily Dose of Math
- 9 Video Solution 3 by Thinking Feet
- 10 Video Solution 4
- 11 Video Solution 5 by CoolMathProblems
- 12 Video Solution 6 by Pi Academy
- 13 See Also
Problem
Lucius is counting backward by s. His first three numbers are
,
, and
. What is his
th number?
Solution 1
We plug and
into the formula
for the
th term of an arithmetic sequence whose first term is
and common difference is
to get
.
~Soupboy0
Solution 2
Since we want to find the th number Lucius says after he says
,
is subtracted from his number
times, so our answer is
~Sigmacuber
Solution 3
Using brute force and counting backward by s, we have
.
Note that this solution is not practical and very time-consuming.
~codegirl2013 ~athreyay
Solution 4
Knowing that our first term is , we have to add
to get to our "0th term",
. To find the answer, we then multiply
by
and subtract that from our 0th term to get to our answer, which is
.
~Kapurnicus ~ Minor edit by NYCnerd
Video Solution 1
~ ChillGuyDoesMath
Video Solution by SpreadTheMathLove
https://www.youtube.com/watch?v=jTTcscvcQmI
Video Solution 2 by Daily Dose of Math
~Thesmartgreekmathdude
Video Solution 3 by Thinking Feet
Video Solution 4
https://youtu.be/VP7g-s8akMY?si=K8Pxs_TQhlR2ntt9&t=211 ~hsnacademy
Video Solution 5 by CoolMathProblems
Video Solution 6 by Pi Academy
https://youtu.be/Iv_a3Rz725w?si=E0SI_h1XT8msWgkK
See Also
2025 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.