Difference between revisions of "1957 AHSME Problems/Problem 36"

(Created page with "By AM-GM, we have <cmath>\frac{x+y}{2} \geq \sqrt{xy}</cmath> Substituting, we have <cmath>\frac{1}{2} \geq \sqrt {xy}</cmath> <cmath>\frac{1}{4} \geq xy</cmath> Equality occu...")
 
(solution edits, see also box, statement of problem)
 
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By AM-GM, we have
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== Problem ==
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If <math>x + y = 1</math>, then the largest value of <math>xy</math> is:
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<math>\textbf{(A)}\ 1\qquad \textbf{(B)}\ 0.5\qquad \textbf{(C)}\ \text{an irrational number about }{0.4}\qquad \textbf{(D)}\ 0.25\qquad\textbf{(E)}\ 0</math>
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== Solution ==
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By [[AM-GM]], we have
 
<cmath>\frac{x+y}{2} \geq \sqrt{xy}</cmath>
 
<cmath>\frac{x+y}{2} \geq \sqrt{xy}</cmath>
 
Substituting, we have
 
Substituting, we have
 
<cmath>\frac{1}{2} \geq \sqrt {xy}</cmath>
 
<cmath>\frac{1}{2} \geq \sqrt {xy}</cmath>
 
<cmath>\frac{1}{4} \geq xy</cmath>
 
<cmath>\frac{1}{4} \geq xy</cmath>
Equality occurs when <math>x = y = \frac{1}{2}</math>
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Equality occurs when <math>x = y = \boxed{\textbf{(D) }\frac12}</math>.
<math>\boxed{D}</math>
 
  
 
~JustinLee2017
 
~JustinLee2017
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== See Also ==
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{{AHSME 50p box|year=1957|num-b=35|num-a=37}}
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{{MAA Notice}}
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[[Category:AHSME]][[Category:AHSME Problems]]

Latest revision as of 08:13, 26 July 2024

Problem

If $x + y = 1$, then the largest value of $xy$ is:

$\textbf{(A)}\ 1\qquad \textbf{(B)}\ 0.5\qquad \textbf{(C)}\ \text{an irrational number about }{0.4}\qquad \textbf{(D)}\ 0.25\qquad\textbf{(E)}\ 0$

Solution

By AM-GM, we have \[\frac{x+y}{2} \geq \sqrt{xy}\] Substituting, we have \[\frac{1}{2} \geq \sqrt {xy}\] \[\frac{1}{4} \geq xy\] Equality occurs when $x = y = \boxed{\textbf{(D) }\frac12}$.

~JustinLee2017

See Also

1957 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 35
Followed by
Problem 37
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All AHSME Problems and Solutions

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