Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "1960 AHSME Problems/Problem 3"

(Solution to Problem 3)
 
(→‎See Also)
Line 15: Line 15:
  
 
==See Also==
 
==See Also==
−
{{AHSME 40p box|year=1960 |before=[[Problem 2]]|after=[[Problem 4]]}}
+
{{AHSME box|year=1960|num-b=2|num-a=4}}

Revision as of 23:29, 7 May 2018

Problem

Applied to a bill for $\textdollar{10,000}$ the difference between a discount of $40$% and two successive discounts of $36$% and $4$%, expressed in dollars, is:

$\textbf{(A)}0\qquad \textbf{(B)}144\qquad \textbf{(C)}256\qquad \textbf{(D)}400\qquad \textbf{(E)}416$

Solution

Taking the discount of $40$% means you're only paying $60$% of the bill. That results in $10,000\cdot0.6=\textdollar{6,000}$.

Likewise, taking two discounts of $36$% and $4$% means taking $64$% of the original amount and then $96$% of the result. That results in $10,000\cdot0.64\cdot0.96=\textdollar{6,144}$.

Taking the difference results in $6,144-6,000=\textdollar{144}$, or answer choice $\boxed{\textbf{(B)}}$.

See Also

1960 AHSME (Problems • Answer Key • Resources)
Preceded by
Problem 2 		Followed by
Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions
Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=1960_AHSME_Problems/Problem_3&oldid=94343"