Difference between revisions of "1960 AHSME Problems/Problem 1"
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==See Also== | ==See Also== | ||
{{AHSME 40p box|year=1960 |before=[[1959 AHSME]]|after=[[Problem 2]]}} | {{AHSME 40p box|year=1960 |before=[[1959 AHSME]]|after=[[Problem 2]]}} | ||
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| + | [[Category:Introductory Algebra Problems]] | ||
Revision as of 17:53, 17 May 2018
Problem
If 
is a solution (root) of 
, then 
equals:
Solution
Substitute for 
. We are given that this equation is true. Solving for gives 
. The answer is 
.
See Also
| 1960 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by 1959 AHSME |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
| All AHSME Problems and Solutions | ||
