Difference between revisions of "1995 AHSME Problems/Problem 3"
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<math> \mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 7 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 9 } \qquad \mathrm{(E) \ 10 } </math> | <math> \mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 7 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 9 } \qquad \mathrm{(E) \ 10 } </math> | ||
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| + | == Solution == | ||
| + | IMPORTANT NOTICE: The original problem statement had "how much is saved". However, because this made little sense when the calculations were done, the problem statement was changed to "how many cents". | ||
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| + | We see that 3 payments of <math>\textdollar 29.98</math> will be a total cost of <math>3\cdot(30-.02)=90-.06</math> | ||
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| + | Adding this to <math>\textdollar9.98</math> we have a total of <math>99.98-.06</math> | ||
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| + | Clearly, this differs from <math>\textdollar 99.99</math> by <math>7</math> cents. Thus, the answer is <math>\fbox{\text{(B)}}</math> | ||
== See also == | == See also == | ||
Revision as of 21:18, 9 February 2012
Problem
The total in-store price for an appliance is 
. A television commercial advertises the same product for three easy payments of 
and a one-time shipping and handling charge of 
. How many cents are saved by buying the appliance from the television advertiser?
Solution
IMPORTANT NOTICE: The original problem statement had "how much is saved". However, because this made little sense when the calculations were done, the problem statement was changed to "how many cents".
We see that 3 payments of will be a total cost of 
Adding this to 
we have a total of 
Clearly, this differs from by 
cents. Thus, the answer is 
See also
| 1995 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
