1995 AHSME Problems/Problem 14
Problem
If and , then
Solution 1
.
Thus .
Solution 2
If , then . Simplifying, we get .
Getting an expression for , we find . Since the first two terms sum up to zero, we get , which is answer
Solution 3
Substituting , we get But , so , which means . Then
See also
1995 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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