Difference between revisions of "2025 AMC 8 Problems/Problem 8"

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==Video Solution by Thinking Feet==
 
==Video Solution by Thinking Feet==
 
https://youtu.be/PKMpTS6b988
 
https://youtu.be/PKMpTS6b988
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==See Also==
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{{AMC8 box|year=2025|num-b=7|num-a=9}}
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{{MAA Notice}}

Revision as of 19:03, 30 January 2025

Problem

Isaiah cuts open a cardboard cube along some of its edges to form the flat shape shown on the right, which has an area of 18 square centimeters. What is the volume of the cube in cubic centimeters?

$\textbf{(A)}~3\sqrt{3}\qquad\textbf{(B)}~6\qquad\textbf{(C)}~9\qquad\textbf{(D)}~6\sqrt{3}\qquad\textbf{(E)}~9\sqrt{3}$

Solution

Observe that since the six squares on the net are congruent, each of them has area $\frac{18}{6}=3$. Hence, the side length of the cube is $\sqrt{3}$. Its volume is then $(\sqrt{3})^3=\boxed{\textbf{(A)}~3\sqrt{3}}$. ~cxsmi

Vide Solution 1 by SpreadTheMathLove

https://www.youtube.com/watch?v=jTTcscvcQmI

Video Solution by Thinking Feet

https://youtu.be/PKMpTS6b988

See Also

2025 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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