Difference between revisions of "1995 AHSME Problems/Problem 3"

(See also)
Line 8: Line 8:
  
 
== See also ==
 
== See also ==
{{Old AMC12 box|year=1995|num-b=2|num-a=4}}
+
{{AHSME box|year=1995|num-b=2|num-a=4}}
  
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]

Revision as of 07:50, 17 April 2008

Problem

The total in-store price for an appliance is $$$99.99$. A television commercial advertises the same product for three easy payments of $$$29.98$ and a one-time shipping and handling charge of $$$9.98$. How many cents are saved by buying the appliance from the television advertiser?

$\mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 7 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 9 } \qquad \mathrm{(E) \ 10 }$

Solution

$99.99 - (29.98*3 + 9.98) = 99.99 - 99.92 = .07 \Rightarrow \mathrm{(B)}$

See also

1995 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions