Difference between revisions of "1957 AHSME Problems/Problem 2"
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| + | == Problem == | ||
| + | |||
| + | In the equation <math>2x^2 - hx + 2k = 0</math>, the sum of the roots is <math>4</math> and the product of the roots is <math>-3</math>. | ||
| + | Then <math>h</math> and <math>k</math> have the values, respectively: | ||
| + | <math>\textbf{(A)}\ 8\text{ and }{-6} \qquad | ||
| + | \textbf{(B)}\ 4\text{ and }{-3}\qquad | ||
| + | \textbf{(C)}\ {-3}\text{ and }4\qquad | ||
| + | \textbf{(D)}\ {-3}\text{ and }8\qquad | ||
| + | \textbf{(E)}\ 8\text{ and }{-3} </math> | ||
| + | |||
| + | == Solution == | ||
| + | <math>\fbox{E}</math> | ||
| + | |||
| + | |||
| + | == See also == | ||
| + | |||
| + | {{AHSME 50p box|year=1957|before=First Problem|num-a=2}} | ||
| + | {{MAA Notice}} | ||
| + | [[Category:AHSME]][[Category:AHSME Problems]] | ||
| + | [[Category:Introductory Algebra Problems]] | ||
Revision as of 10:02, 24 July 2024
Problem
In the equation 
, the sum of the roots is 
and the product of the roots is 
.
Then 
and 
have the values, respectively:
Solution
See also
| 1957 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
