Difference between revisions of "2025 AMC 8 Problems/Problem 6"

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== Solution 1 ==
 
== Solution 1 ==
  
The sum of all five numbers is <math>85</math>. Since <math>85</math> is <math>1</math> more than a multiple of <math>4</math>, the number subtracted must be <math>1</math> more than a multiple of <math>4</math>. Thus, the answer is <math>\boxed{\textbf{(C)}~17}</math>.
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The sum of all five numbers is <math>85</math>. Since <math>85</math> is <math>1</math> more than a multiple of <math>4</math>, the number being subtracted must be <math>1</math> more than a multiple of <math>4</math>. Thus, the answer is <math>\boxed{\textbf{(C)}~17}</math>.
 
~Gavin_Deng
 
~Gavin_Deng
  
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== Solution 3 ==  
 
== Solution 3 ==  
  
We try out every number using [[brute force]] and get <math>\boxed{\textbf{(C)}~17}</math>
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We try out every number using [[brute force]] and get <math>\boxed{\textbf{(C)}~17}</math>.
  
Note that this is not very practical and it is very time-consuming.
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Note that this is not practical and it is very time-consuming.
  
== Video Solution 1 by SpreadTheMathLove ==
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== Video Solution 1 by Cool Math Problems ==
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 +
https://youtu.be/BRnILzqVwHk?si=1KwyuFBUDqdMtC6t&t=2
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 +
== Video Solution 2 by SpreadTheMathLove ==
  
 
https://www.youtube.com/watch?v=jTTcscvcQmI
 
https://www.youtube.com/watch?v=jTTcscvcQmI
  
==Video Solution (A Clever Explanation You’ll Get Instantly)==
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== Video Solution 3 ==
https://youtu.be/VP7g-s8akMY?si=eMjbNcrUSiSp30ND&t=324
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~hsnacademy
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[//youtu.be/VP7g-s8akMY?si=eMjbNcrUSiSp30ND&t=324 ~hsnacademy]
  
== Video Solution 2 by Thinking Feet ==
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== Video Solution 4 by Thinking Feet ==
  
 
https://youtu.be/PKMpTS6b988
 
https://youtu.be/PKMpTS6b988
  
==Video Solution by Daily Dose of Math==
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== Video Solution 5 by Daily Dose of Math ==
 
 
https://youtu.be/nkpdskFVgdM
 
  
~Thesmartgreekmathdude
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[//youtu.be/nkpdskFVgdM ~Thesmartgreekmathdude]
  
 
== See Also ==
 
== See Also ==

Latest revision as of 21:32, 3 February 2025

Problem

Sekou writes the numbers $15, 16, 17, 18, 19.$ After he erases one of his numbers, the sum of the remaining four numbers is a multiple of $4.$ Which number did he erase?

$\textbf{(A)}\ 15\qquad \textbf{(B)}\ 16\qquad \textbf{(C)}\ 17\qquad \textbf{(D)}\ 18\qquad \textbf{(E)}\ 19$

Solution 1

The sum of all five numbers is $85$. Since $85$ is $1$ more than a multiple of $4$, the number being subtracted must be $1$ more than a multiple of $4$. Thus, the answer is $\boxed{\textbf{(C)}~17}$. ~Gavin_Deng

Solution 2

The sum of the residues of these numbers modulo $4$ is $-1+0+1+2+3=5 \equiv 1 \pmod 4$. Hence, the number being subtracted must be congruent to $1$ modulo $4$. The only such answer is $\boxed{\textbf{(C)}~17}$. ~cxsmi

Solution 3

We try out every number using brute force and get $\boxed{\textbf{(C)}~17}$.

Note that this is not practical and it is very time-consuming.

Video Solution 1 by Cool Math Problems

https://youtu.be/BRnILzqVwHk?si=1KwyuFBUDqdMtC6t&t=2

Video Solution 2 by SpreadTheMathLove

https://www.youtube.com/watch?v=jTTcscvcQmI

Video Solution 3

~hsnacademy

Video Solution 4 by Thinking Feet

https://youtu.be/PKMpTS6b988

Video Solution 5 by Daily Dose of Math

~Thesmartgreekmathdude

See Also

2025 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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