Difference between revisions of "2025 AMC 8 Problems/Problem 6"
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== Solution 1 == | == Solution 1 == | ||
− | The sum of all five numbers is <math>85</math>. Since <math>85</math> is <math>1</math> more than a multiple of <math>4</math>, the number subtracted must be <math>1</math> more than a multiple of <math>4</math>. Thus, the answer is <math>\boxed{\textbf{(C)}~17}</math>. | + | The sum of all five numbers is <math>85</math>. Since <math>85</math> is <math>1</math> more than a multiple of <math>4</math>, the number being subtracted must be <math>1</math> more than a multiple of <math>4</math>. Thus, the answer is <math>\boxed{\textbf{(C)}~17}</math>. |
~Gavin_Deng | ~Gavin_Deng | ||
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== Solution 3 == | == Solution 3 == | ||
− | We try out every number using [[brute force]] and get <math>\boxed{\textbf{(C)}~17}</math> | + | We try out every number using [[brute force]] and get <math>\boxed{\textbf{(C)}~17}</math>. |
− | Note that this is not | + | Note that this is not practical and it is very time-consuming. |
− | == Video Solution 1 by SpreadTheMathLove == | + | == Video Solution 1 by Cool Math Problems == |
+ | |||
+ | https://youtu.be/BRnILzqVwHk?si=1KwyuFBUDqdMtC6t&t=2 | ||
+ | |||
+ | == Video Solution 2 by SpreadTheMathLove == | ||
https://www.youtube.com/watch?v=jTTcscvcQmI | https://www.youtube.com/watch?v=jTTcscvcQmI | ||
− | ==Video Solution | + | == Video Solution 3 == |
− | + | ||
− | ~hsnacademy | + | [//youtu.be/VP7g-s8akMY?si=eMjbNcrUSiSp30ND&t=324 ~hsnacademy] |
− | == Video Solution | + | == Video Solution 4 by Thinking Feet == |
https://youtu.be/PKMpTS6b988 | https://youtu.be/PKMpTS6b988 | ||
− | ==Video Solution by Daily Dose of Math== | + | == Video Solution 5 by Daily Dose of Math == |
− | |||
− | |||
− | ~Thesmartgreekmathdude | + | [//youtu.be/nkpdskFVgdM ~Thesmartgreekmathdude] |
== See Also == | == See Also == |
Latest revision as of 21:32, 3 February 2025
Contents
Problem
Sekou writes the numbers After he erases one of his numbers, the sum of the remaining four numbers is a multiple of
Which number did he erase?
Solution 1
The sum of all five numbers is . Since
is
more than a multiple of
, the number being subtracted must be
more than a multiple of
. Thus, the answer is
.
~Gavin_Deng
Solution 2
The sum of the residues of these numbers modulo is
. Hence, the number being subtracted must be congruent to
modulo
. The only such answer is
.
~cxsmi
Solution 3
We try out every number using brute force and get .
Note that this is not practical and it is very time-consuming.
Video Solution 1 by Cool Math Problems
https://youtu.be/BRnILzqVwHk?si=1KwyuFBUDqdMtC6t&t=2
Video Solution 2 by SpreadTheMathLove
https://www.youtube.com/watch?v=jTTcscvcQmI
Video Solution 3
Video Solution 4 by Thinking Feet
Video Solution 5 by Daily Dose of Math
See Also
2025 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.