Difference between revisions of "2025 AMC 8 Problems/Problem 9"

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==Problem==
 
==Problem==
 
Ningli looks at the 6 pairs of numbers directly across from each other on a clock. She takes the average of each pair of numbers. What is the average of the resulting 6 numbers?
 
Ningli looks at the 6 pairs of numbers directly across from each other on a clock. She takes the average of each pair of numbers. What is the average of the resulting 6 numbers?
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[[File:Amc8_2025_prob9.PNG]]
  
 
<math>\textbf{(A)}\ 5\qquad \textbf{(B)}\ 6.5\qquad \textbf{(C)}\ 8\qquad \textbf{(D)}\ 9.5 \qquad \textbf{(E)}\ 12</math>
 
<math>\textbf{(A)}\ 5\qquad \textbf{(B)}\ 6.5\qquad \textbf{(C)}\ 8\qquad \textbf{(D)}\ 9.5 \qquad \textbf{(E)}\ 12</math>
  
 
==Solution 1==
 
==Solution 1==
Notice that this is simply the sum of the numbers on the clock face divided by <math>12</math>. Why? This is because for a given number, it will be divided by <math>2</math> due to its averaging with its counterpart on the other side of the clock face, and then it will be divided by <math>6</math> when we average out all the smaller averages. Since the sum of the first <math>12</math> positive integers is <math>78</math>, our answer is <math>\frac{78}{12}=\boxed{\textbf{(B)}~6.5}</math>. ~cxsmi
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The answer can be expressed as (1+7)/2 + (2 + 8)/2 + ... + (6 + 12)/2, with the whole result divided by 6. Therefore, the answer of the question is the sum of the numbers from 1 through 12 divided by 2 * 6 = 12. The answer is 12/2 = 6 * 13 = 78/12, leading to the answer <math>\frac{78}{12}=\boxed{\textbf{(B)}~6.5}</math>.
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~Sigmacuber
  
 
==Solution 2==
 
==Solution 2==
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~Bepin999
 
~Bepin999
  
==Vide Solution 1 by SpreadTheMathLove==
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==Video Solution 1 by SpreadTheMathLove==
 
https://www.youtube.com/watch?v=jTTcscvcQmI
 
https://www.youtube.com/watch?v=jTTcscvcQmI
  
 
==Video Solution by Thinking Feet==
 
==Video Solution by Thinking Feet==
 
https://youtu.be/PKMpTS6b988
 
https://youtu.be/PKMpTS6b988
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==See Also==
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{{AMC8 box|year=2025|num-b=8|num-a=10}}
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{{MAA Notice}}

Latest revision as of 00:21, 31 January 2025

Problem

Ningli looks at the 6 pairs of numbers directly across from each other on a clock. She takes the average of each pair of numbers. What is the average of the resulting 6 numbers?

Amc8 2025 prob9.PNG

$\textbf{(A)}\ 5\qquad \textbf{(B)}\ 6.5\qquad \textbf{(C)}\ 8\qquad \textbf{(D)}\ 9.5 \qquad \textbf{(E)}\ 12$

Solution 1

The answer can be expressed as (1+7)/2 + (2 + 8)/2 + ... + (6 + 12)/2, with the whole result divided by 6. Therefore, the answer of the question is the sum of the numbers from 1 through 12 divided by 2 * 6 = 12. The answer is 12/2 = 6 * 13 = 78/12, leading to the answer $\frac{78}{12}=\boxed{\textbf{(B)}~6.5}$.

~Sigmacuber

Solution 2

The pairs for the opposite numbers on the clock are $(12,6)$, $(1,7)$, $(2,8)$, $(3,9)$, $(4,10)$, and $(5,11)$. The averages of each of these pairs are $9, 4, 5, 6, 7,$ and $8$ respectively. The averages of $9, 4, 5, 6, 7,$ and $8$ are $\frac{39}{6}=\boxed{\textbf{(B)}~6.5}$

~Bepin999

Video Solution 1 by SpreadTheMathLove

https://www.youtube.com/watch?v=jTTcscvcQmI

Video Solution by Thinking Feet

https://youtu.be/PKMpTS6b988

See Also

2025 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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