Difference between revisions of "1973 Canadian MO Problems/Problem 4"

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==Problem==
 
==Problem==
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<asy>
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size(200);
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pair A=dir(120), B=dir(80);
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for(int k=0;k<9;++k)
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{
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pair C=dir(120-(40)*(k+2));
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D(A--B);
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A=B;B=C;
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}
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for(int k=0;k<3;++k)
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{
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pair A1=dir(120-(40)*(3*k));
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pair B1=dir(120-(40)*(3*k+2));
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pair C1=dir(120-(40)*(3*k+3));
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D(A1--B1);
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D(A1--C1);
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}
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for(int k=0;k<9;++k)
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{
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pair A=dir(120+(40)*(k));
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MP("P_{"+string(k)+"}",A,11,A);
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}
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</asy>
  
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The figure shows a (convex) polygon with nine vertices. The six diagonals which have been drawn dissect the polygon into the seven triangles: <math>P_{0}P_{1}P_{3},~ P_{0}P_{3}P_{6},~  P_{0}P_{6}P_{7},~ P_{0}P_{7}P_{8},~  P_{1}P_{2}P_{3}, ~ P_{3}P_{4}P_{6},~ P_{4}P_{5}P_{6}</math>. In how many ways can these triangles be labeled with the names <math>\triangle_{1}, ~ \triangle_{2}, ~ \triangle_{3}, ~ \triangle_{4}, ~ \triangle_{5},~  \triangle_{6},~  \triangle_{7}</math> so that <math>P_{i}</math> is a vertex of triangle <math>\triangle_{i}</math> for <math>i = 1, 2, 3, 4, 5, 6, 7</math>? Justify your answer.
  
 
==Solution==
 
==Solution==

Latest revision as of 17:24, 8 October 2014

Problem

[asy] size(200); pair A=dir(120), B=dir(80); for(int k=0;k<9;++k) { pair C=dir(120-(40)*(k+2)); D(A--B); A=B;B=C; } for(int k=0;k<3;++k) { pair A1=dir(120-(40)*(3*k)); pair B1=dir(120-(40)*(3*k+2)); pair C1=dir(120-(40)*(3*k+3)); D(A1--B1); D(A1--C1); } for(int k=0;k<9;++k) { pair A=dir(120+(40)*(k)); MP("P_{"+string(k)+"}",A,11,A); } [/asy]

The figure shows a (convex) polygon with nine vertices. The six diagonals which have been drawn dissect the polygon into the seven triangles: $P_{0}P_{1}P_{3},~ P_{0}P_{3}P_{6},~  P_{0}P_{6}P_{7},~ P_{0}P_{7}P_{8},~  P_{1}P_{2}P_{3}, ~ P_{3}P_{4}P_{6},~ P_{4}P_{5}P_{6}$. In how many ways can these triangles be labeled with the names $\triangle_{1}, ~ \triangle_{2}, ~ \triangle_{3}, ~ \triangle_{4}, ~ \triangle_{5},~  \triangle_{6},~  \triangle_{7}$ so that $P_{i}$ is a vertex of triangle $\triangle_{i}$ for $i = 1, 2, 3, 4, 5, 6, 7$? Justify your answer.

Solution

See also

1973 Canadian MO (Problems)
Preceded by
Problem 3
1 2 3 4 5 Followed by
Problem 5