Difference between revisions of "2007 AMC 8 Problems/Problem 5"
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== Problem == | == Problem == | ||
− | Chandler wants to buy a <math>$</ | + | Chandler wants to buy a <math>$500</math> mountain bike. For his birthday, his grandparents |
− | send him < | + | send him <math>$50</math>, his aunt sends him <math>$35</math> and his cousin gives him <math>$15</math>. He earns |
− | <math>$</ | + | <math>$16</math> per week for his paper route. He will use all of his birthday money and all |
of the money he earns from his paper route. In how many weeks will he be able | of the money he earns from his paper route. In how many weeks will he be able | ||
to buy the mountain bike? | to buy the mountain bike? | ||
− | < | + | <math>\mathrm{(A)}\ 24 \qquad\mathrm{(B)}\ 25 \qquad\mathrm{(C)}\ 26 \qquad\mathrm{(D)}\ 27 \qquad\mathrm{(E)}\ 28</math> |
== Solution == | == Solution == | ||
− | Let < | + | Let <math>x</math> be the number of weeks. |
− | Thus, we have the equation < | + | Thus, we have the equation <math>50 + 35 + 15 + 16x = 500</math>. |
Simplify, | Simplify, | ||
− | < | + | <math>100 + 16x = 500</math> |
− | < | + | <math>16x = 400</math> |
− | < | + | <math>x = 25</math> |
− | The answer is < | + | The answer is <math> \boxed{\textbf{(B)}\ 25} </math> |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2007|num-b=4|num-a=6}} | {{AMC8 box|year=2007|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 13:25, 18 November 2013
Problem
Chandler wants to buy a mountain bike. For his birthday, his grandparents send him , his aunt sends him and his cousin gives him . He earns per week for his paper route. He will use all of his birthday money and all of the money he earns from his paper route. In how many weeks will he be able to buy the mountain bike?
Solution
Let be the number of weeks.
Thus, we have the equation .
Simplify,
The answer is
See Also
2007 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.