Difference between revisions of "1995 AHSME Problems/Problem 2"

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== See also ==
 
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[[Category:Introductory Algebra Problems]]
 
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{{MAA Notice}}

Latest revision as of 12:58, 5 July 2013

Problem

If $\sqrt {2 + \sqrt {x}} = 3$, then $x =$

$\mathrm{(A) \ 1 } \qquad \mathrm{(B) \ \sqrt{7} } \qquad \mathrm{(C) \ 7 } \qquad \mathrm{(D) \ 49 } \qquad \mathrm{(E) \ 121 }$

Solution

$2 + \sqrt{x} = 9 \Longrightarrow \sqrt{x} = 7 \Longrightarrow x = 49 \Rightarrow \mathrm{(D)}$

See also

1995 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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