Difference between revisions of "2025 AIME II Problems/Problem 15"

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== Solution ==
 
== Solution ==
 
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{{alternate solutions}}
 
==See also==
 
==See also==
 
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Revision as of 03:09, 14 February 2025

Problem

Let \[f(x)=\frac{(x-18)(x-72)(x-98)(x-k)}{x}.\]There exist exactly three positive real values of $k$ such that $f$ has a minimum at exactly two real values of $x$. Find the sum of these three values of $k$.

Solution

Alternate solutions are always welcome. If you have a different, elegant solution to this problem, please add it to this page.

See also

2025 AIME II (ProblemsAnswer KeyResources)
Preceded by
Problem 14
Followed by
Last Problem
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions

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