Difference between revisions of "2007 AMC 8 Problems/Problem 4"

Latest revision as of 16:30, 28 October 2024

A haunted house has six windows. In how many ways can Georgie the Ghost enter the house by one window and leave by a different window?

$\mathrm{(A)}\ 12 \qquad\mathrm{(B)}\ 15 \qquad\mathrm{(C)}\ 18 \qquad\mathrm{(D)}\ 30 \qquad\mathrm{(E)}\ 36$

Georgie can enter the haunted house through any of the six windows. Then, he can leave through any of the remaining five windows.

So, Georgie has a total of $6 \cdot 5$ ways he can enter the house by one window and leave by a different window.

Therefore, we have $\boxed{\textbf{(D)}\ 30}$ ways.

2007 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 3	Followed by Problem 5
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

@@ Line 11: / Line 11: @@
 Georgie can enter the haunted house through any of the six windows. Then, he can leave through any of the remaining five windows.
-So, Georgie has a total of <math>6 * 5</math> ways he can enter the house by one window and leave
+So, Georgie has a total of <math>6 \cdot 5</math> ways he can enter the house by one window and leave
 by a different window.
-Our answer is <math>30</math>, <math>\boxed{D}</math>
+Therefore, we have <math> \boxed{\textbf{(D)}\ 30} </math> ways.
+==Video Solution by SpreadTheMathLove==
+https://www.youtube.com/watch?v=omFpSGMWhFc
+==Video Solution by WhyMath==
+https://youtu.be/XdnS_5KEx6s
 ==See Also==
 {{AMC8 box|year=2007|num-b=3|num-a=5}}
+{{MAA Notice}}