Difference between revisions of "2007 AMC 8 Problems/Problem 3"

Latest revision as of 16:30, 28 October 2024

What is the sum of the two smallest prime factors of $250$ ?

$\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12$

The prime factorization of $250$ is $2 \cdot 5^3$ . The smallest two are $2$ and $5$ . $2+5 = \boxed{\text{(C) }7}$ .

2007 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

@@ Line 4: / Line 4: @@
 <math>\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12</math>
+==Video Solution by OmegaLearn==
+https://youtu.be/7an5wU9Q5hk?t=272
 == Solution ==
-We prime factor <math>250 = 2\cdot 5^3</math>. The smallest two are <math>2</math> and <math>5</math>. <math>2+5 = \boxed{\text{C}}</math>
+The prime factorization of <math>250</math> is <math>2 \cdot 5^3</math>. The smallest two are <math>2</math> and <math>5</math>. <math>2+5 = \boxed{\text{(C) }7}</math>.
+==Video Solution by SpreadTheMathLove==
+https://www.youtube.com/watch?v=omFpSGMWhFc
+==Video Solution by WhyMath==
+https://youtu.be/_8lDRd1FEd4
 ==See Also==
 {{AMC8 box|year=2007|num-b=2|num-a=4}}
 {{MAA Notice}}