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| − | == Problem ==
| + | #redirect [[2006 AMC 12A Problems/Problem 14]] |
| − | Two farmers agree that pigs are worth $300 and that goats are worth $210. When one farmer owes the other money, he pays the debt in pigs or goats, with "change" received in the form of goats or pigs as necessary. (For example, a $390 debt could be paid with two pigs, with one goat received in change.) What is the amount of the smallest positive debt that can be resolved in this way?
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| − | <math>\mathrm{(A) \ } $5\qquad\mathrm{(B) \ } $10\qquad\mathrm{(C) \ } $30\qquad\mathrm{(D) \ } $90\qquad\mathrm{(E) \ } $210\qquad</math>
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| − | == Solution ==
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| − | The problem can be restated as an equation of the form 300''p'' + 210''g'' = ''x'', where ''p'' is the number of pigs, ''g'' is the number of goats, and ''x'' is the positive debt. The problem asks us to find the lowest ''x'' possible. ''p'' and ''g'' must be integers, which makes the equation a Diophantine equation. Anyone with knowledge of number theory would know that there are integer solutions to a Diophantine equation if it is in the form ax + by = c, where c is the greatest common denominator of a and b. Therefore, the answer is simply the greatest common denominator of 300 and 210, which is, of course, 30 (c)
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| − | == See also ==
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| − | *[[2006 AMC 10A Problems]]
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