Difference between revisions of "2005 AMC 12B Problems/Problem 2"
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| + | {{Duplicate|[[2005 AMC 12B Problems|2005 AMC 12B #2]] and [[2005 AMC 10B Problems|2005 AMC 10B #2]]}} | ||
| + | |||
== Problem == | == Problem == | ||
| + | A positive number <math>x</math> has the property that <math>x\%</math> of <math>x</math> is <math>4</math>. What is <math>x</math>? | ||
| + | |||
| + | <math> | ||
| + | \textbf{(A) }\ 2 \qquad | ||
| + | \textbf{(B) }\ 4 \qquad | ||
| + | \textbf{(C) }\ 10 \qquad | ||
| + | \textbf{(D) }\ 20 \qquad | ||
| + | \textbf{(E) }\ 40 | ||
| + | </math> | ||
== Solution == | == Solution == | ||
| + | |||
| + | ===Solution 1=== | ||
| + | |||
| + | Since <math>x\%</math> means <math>0.01x</math>, the statement "<math>x\% \text{ of } x \text{ is 4}</math>" can be rewritten as "<math>0.01x \cdot x = 4</math>": | ||
| + | |||
| + | <math>0.01x \cdot x=4 \Rightarrow x^2 = 400 \Rightarrow x = \boxed{\textbf{(D) }20}.</math> | ||
| + | |||
| + | ===Solution 2=== | ||
| + | |||
| + | Try the answer choices one by one. Upon examination, it is quite obvious that the answer is <math>\boxed{\textbf{(D) }20}.</math> Very fast. | ||
| + | |||
| + | |||
| + | Solution by franzliszt | ||
== See also == | == See also == | ||
| − | + | {{AMC10 box|year=2005|ab=B|num-b=1|num-a=3}} | |
| + | {{AMC12 box|year=2005|ab=B|num-b=1|num-a=3}} | ||
| + | [[Category:Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 12:56, 14 December 2021
- The following problem is from both the 2005 AMC 12B #2 and 2005 AMC 10B #2, so both problems redirect to this page.
Problem
A positive number 
has the property that 
of is 
. What is ?
Solution
Solution 1
Since means 
, the statement "
" can be rewritten as "
":
Solution 2
Try the answer choices one by one. Upon examination, it is quite obvious that the answer is 
Very fast.
Solution by franzliszt
See also
| 2005 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2005 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
