Difference between revisions of "2006 AMC 12A Problems/Problem 16"
(box, solution) |
m (→See also: convert) |
||
Line 15: | Line 15: | ||
* [[2006 AMC 12A Problems]] | * [[2006 AMC 12A Problems]] | ||
− | {{ | + | {{AMC12 box|year=2006|ab=A|num-b=15|num-a=17}} |
[[Category:Introductory Geometry Problems]] | [[Category:Introductory Geometry Problems]] |
Revision as of 18:21, 2 February 2007
Problem
An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.
Circles with centers and have radii and , respectively. A common internal tangent intersects the circles at and , respectively. Lines and intersect at , and . What is ?
Solution
and (vertical angles) are congruent, as are right angles and (since radii intersect tangents at right angles). Thus, .
By the Pythagorean Theorem, line segment . The sides are proportional, so . This makes and .
See also
2006 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 15 |
Followed by Problem 17 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |