Talk:1999 AIME Problems/Problem 12
Let ABC be an inscribed triangle (O). On two sides AB, AC take points E, F such that BE = EF = FC. The tangent at A of (O) intersects EF at P. I is the center of the incircle of triangle AEF. Prove that PI = PA.
Let ABC be an inscribed triangle (O). On two sides AB, AC take points E, F such that BE = EF = FC. The tangent at A of (O) intersects EF at P. I is the center of the incircle of triangle AEF. Prove that PI = PA.
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