User contributions
- 15:52, 28 February 2021 (diff | hist) . . (+254) . . N If no one shares an office, in how many ways can 3 people be assigned to 5 different offices? (Each person gets exactly one office). (So, there are 60 possible ways to assign the three people to offices.)
- 15:49, 28 February 2021 (diff | hist) . . (+97) . . N The local theater has one ticket window. In how many ways can six people line up to buy a ticket? (We must count the number of permutations of 6 people. There are 6 choices for the first person in line, 5 choices for the second person in line, etc. So the answer is $6\cdot5\cdot 4\cdot 3\cdot2\cdot 1=\boxed{720}$.)
