MIE 2016/Day 1/Problem 6

Problem 6

Let $A$ be $A=\begin{vmatrix}1&a&-2\\a-2&1&1\\2&-3&1\end{vmatrix}$ with $a\in\mathbb{R}$ . We know that $\text{det}(A^2-2A+I)=16$ . The sum of the values of $a$ that satisfies this condition is:

(a) $0$

(b) $1$

(c) $2$

(d) $3$

(e) $4$

Note: $\text{det}(X)$ is the determinant of the matrix $X$ .

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MIE 2016/Day 1/Problem 6

Problem 6

Solution

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