AoPS Wiki talk:Problem of the Day/August 2, 2011
Problem: Find all such that
and
.
Solution: Let and
. Then
and
. Hence,
This quartic has two real roots;
and
by the cubic formula. Call this second root (which evaluates to about -3.01)
. The two real solutions are therefore:
and
There are more solutions in , corresponding to the complex roots of
.