2015 UNCO Math Contest II Problems/Problem 1

Problem

The sum of three consecutive integers is $54$ . What is the smallest of the three integers?

Solution

Call the smallest integer $x$ . We can express the sum as $(x) + (x + 1) + (x + 2)$ . Solving, we get $(x) + (x + 1) + (x + 2) = 54 \implies 3x + 3 = 54 \implies 3x = 51 \implies x = \boxed{17}$ .

2015 UNCO Math Contest II (Problems • Answer Key • Resources)
Preceded by First Question	Followed by Problem 2
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2015 UNCO Math Contest II Problems/Problem 1

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