2004 AMC 8 Problems/Problem 1

Problem

On a map, a $12$ -centimeter length represents $72$ kilometers. How many kilometers does a $17$ -centimeter length represent?

$\textbf{(A)}\ 6\qquad\textbf{(B)}\ 102\qquad\textbf{(C)}\ 204\qquad\textbf{(D)}\ 864\qquad\textbf{(E)}\ 1224$

Solution

We set up the proportion $\frac{12 \text{cm}}{72 \text{km}}=\frac{17 \text{cm}}{x \text{km}}$ . Thus $x=102 \Rightarrow \boxed{\textbf{(B)}\ 102}$

Solution 2

Since we know $12$ centimeters on the map is equal to $72$ kilometers, $1$ centimeter on the map is simply $72/12$ , which is $6$ . The problem is asking how many kilometers a $17$ -centimeter length represents, so we multiply $6$ by $17$ which is simply 102, your answer.

2004 AMC 8 (Problems • Answer Key • Resources)
Preceded by First Question	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

Page

Toolbox

Search

2004 AMC 8 Problems/Problem 1

Contents

Problem

Solution

Solution 2

See Also