2003 AMC 10B Problems/Problem 12
Problem
Al, Betty, and Clare split among them to be invested in different ways. Each begins with a different amount. At the end of one year, they have a total of dollars. Betty and Clare have both doubled their money, whereas Al has managed to lose dollars. What was Al's original portion?
Solution 1
For this problem, we will have to write a three-variable equation, but not necessarily solve it. Let and represent the original portions of Al, Betty, and Clare, respectively. At the end of one year, they each have and . From this, we can write two equations.
Since all we need to find is subtract the second equation from the first equation to get Al's original portion was .
Solution 2
Suppose Betty and Clare dollars and Al dollars originally. Then, , so Al's original portion was .
~Mathkiddie
Solution 3
If Al had not lost , the total amount would be . So, Betty and Clare collectively gained and as they have doubled their collective fortune, they must have with them at the beginning. This leaves for Al. ~Anshulb
Solution 4
Let and represent the original portions of Al, Betty, and Clare, respectively. We can write some equations: Subtracting the first equation from the second we get . So,
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See Also
2003 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
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All AMC 10 Problems and Solutions |
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