1963 TMTA High School Algebra I Contest Problem 6

Problem

$(3x+2)(4x-5)$ is equal to:

$\text{(A)} \quad 12x^2-10 \quad \text{(B)} \quad 12x^2-23x-10 \quad \text{(C)} \quad 12x^3+7x-10$

$\text{(D)} \quad 12x^2-7x-10 \quad \text{(E) NOTA}$

Use the FOIL method to expand: $(3x+2)(4x-5) = 12x^2 + 8x- 15x - 10 = \boxed{12x^2- 7x-10}$ The answer is $\boxed{\text{(D)}}.$

1963 TMTA High School Mathematics Contests (Problems)
Preceded by Problem 5	TMTA High School Mathematics Contest Past Problems/Solutions	Followed by Problem 7