1957 AHSME Problems/Problem 27

Revision as of 17:49, 20 October 2018 by The referee (talk | contribs) (Created page with "One approach is to plug in some roots. You have <math>x^{2}-5x+6=0</math> The roots are <math>x=2</math> and <math>x=3</math>. The sum of the roots is <math>\frac{1}{2}+\f...")
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One approach is to plug in some roots.

You have $x^{2}-5x+6=0$

The roots are $x=2$ and $x=3$.

The sum of the roots is $\frac{1}{2}+\frac{1}{3}=\frac{5}{6}$.

In this case, $p$ and $q$ are $-5$ and $6$.

From there, you can easily tell that the answer is $(A)$