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MIE 2016/Day 1/Problem 7

Revision as of 20:45, 7 January 2018 by Anishanne (talk | contribs) (Created page with "===Problem 7=== The product of the real roots of the following equation is equal to: <math>y^{\log_3\sqrt{3y}}=y^{\log_33y}-6,~~y>0</math> (a) <math>\frac{1}{3}</math> (b)...")
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Problem 7

The product of the real roots of the following equation is equal to:

$y^{\log_3\sqrt{3y}}=y^{\log_33y}-6,~~y>0$


(a) $\frac{1}{3}$

(b) $\frac{1}{2}$

(c) $\frac{3}{4}$

(d) $2$

(e) $3$

Solution

See Also

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