1992 AJHSME Problems/Problem 8

Problem

A store owner bought $1500$ pencils at $$0.10$ each. If he sells them for <dollar/>0.25 each, how many of them must he sell to make a profit of exactly $$100.00$ ?

$\text{(A)}\ 400 \qquad \text{(B)}\ 667 \qquad \text{(C)}\ 1000 \qquad \text{(D)}\ 1500 \qquad \text{(E)}\ 1900$

Solution

$1500\times 0.1=150$ , so the store owner is <dollar/>150 below profit. Therefore he needs to sell $150+100= 250$ dollars worth of pencils. Selling them at <dollar/>0.25 each gives $250/0.25= \boxed{\textbf{(C)}\ 1000}$ .

1992 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 7	Followed by Problem 9
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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1992 AJHSME Problems/Problem 8

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