1994 AJHSME Problems/Problem 3

Problem

Each day Maria must work $8$ hours. This does not include the $45$ minutes she takes for lunch. If she begins working at $\text{7:25 A.M.}$ and takes her lunch break at noon, then her working day will end at

$\text{(A)}\ \text{3:40 P.M.} \qquad \text{(B)}\ \text{3:55 P.M.} \qquad \text{(C)}\ \text{4:10 P.M.} \qquad \text{(D)}\ \text{4:25 P.M.} \qquad \text{(E)}\ \text{4:40 P.M.}$

Solution

8 hours from 7:25 AM is 15:25 or 3:25 PM. 45 minutes from 25 minutes is 10 minutes after the hour, so her working day ends at $\boxed{\text{(C)}\ \text{4:10 P.M.}}$

-The Hacker

1994 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
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1994 AJHSME Problems/Problem 3

Contents

Problem

Solution

-The Hacker

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