1991 AHSME Problems/Problem 29

Problem

Equilateral triangle $ABC$ has $P$ on $AB$ and $Q$ on $AC$ . The triangle is folded along $PQ$ so that vertex $A$ now rests at $A'$ on side $BC$ . If $BA'=1$ and $A'C=2$ then the length of the crease $PQ$ is

$\text{(A) } \frac{8}{5} \text{(B) } \frac{7}{20}\sqrt{21} \text{(C) } \frac{1+\sqrt{5}}{2} \text{(D) } \frac{13}{8} \text{(E) } \sqrt{3}$

Solution

$\fbox{B}$

1991 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 28	Followed by Problem 30
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1991 AHSME Problems/Problem 29

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