Problem

For a certain positive integer n less than $1000$ , the decimal equivalent of $\frac{1}{n}$ is $0.\overline{abcdef}$ , a repeating decimal of period of 6, and the decimal equivalent of $\frac{1}{n+6}$ is $0.\overline{wxyz}$ , a repeating decimal of period 4. In which interval does $n$ lie?

$\textbf{(A)}\ [1,200]\qquad\textbf{(B)}\ [201,400]\qquad\textbf{(C)}\ [401,600]1\qquad\textbf{(D)}\ [601,800]\qquad\textbf{(E)}\ [801,999]$

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2016 AMC 12B Problems/Problem 22

Problem