2016 AMC 10B Problems/Problem 8

Revision as of 10:22, 21 February 2016 by Xturtlex (talk | contribs) (Solution)

Problem

What is the tens digit of $2015^{2016}-2017?$

$\textbf{(A)}\ 0 \qquad \textbf{(B)}\ 1 \qquad \textbf{(C)}\ 3 \qquad \textbf{(D)}\ 5 \qquad \textbf{(E)}\ 8$

Solution

We notice that $2015^{n}$ is $25 (mod 100)$ when $n is even$ and $75 (mod 100)$ when $n is odd.$ (Check for yourself). Since 2016 is even, $2015^{2016}$ is 25 (mod 100) and $2015^{2016}-2017 \equiv 25 - 17 \equiv 08 (mod  100)$

So the answer is $\textbf{(A)}\ 0 \qquad$

solution by Wwang