2011 UNCO Math Contest II Problems/Problem 1

Revision as of 00:00, 21 December 2014 by Pi3point14 (talk | contribs) (Solution)

Problem

The largest integer $n$ so that $3^n$ evenly divides $9! = 1\cdot 2\cdot 3\cdot 4\cdot 5\cdot 6\cdot 7\cdot 8\cdot 9$ is $n = 4$. Determine the largest integer $n$ so that $3^n$ evenly divides $85! = 1\cdot 2\cdot 3\cdot 4\cdots 84\cdot 85$.


Solution

Let int(x) indicate the largest integer less than or equal to x. To solve this problem, we simply need to find the powers of 3 that go into 85. Thus we get int(85/3). But that doesn't count the 2 3's in 9, so we need to add that to int(85/9), int(85/27), and int(85/81), giving us 41.

See Also

2011 UNCO Math Contest II (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10
All UNCO Math Contest Problems and Solutions