1969 AHSME Problems/Problem 1

Problem

When $x$ is added to both the numerator and denominator of the fraction $\frac{a}{b},a \ne b,b \ne 0$ , the value of the fraction is changed to $\frac{c}{d}$ . Then $x$ equals:

$\text{(A) } \frac{1}{c-d}\quad \text{(B) } \frac{ad-bc}{c-d}\quad \text{(C) } \frac{ad-bc}{c+d}\quad \text{(D) }\frac{bc-ad}{c-d} \quad \text{(E) } \frac{bc+ad}{c-d}$

Solution

$\fbox{B}$

1969 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 2
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All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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1969 AHSME Problems/Problem 1

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