1967 AHSME Problems/Problem 23

Problem

If $x$ is real and positive and grows beyond all bounds, then $\log_3{(6x-5)}-\log_3{(2x+1)}$ approaches:

$\textbf{(A)}\ 0\qquad \textbf{(B)}\ 1\qquad \textbf{(C)}\ 3\qquad \textbf{(D)}\ 4\qquad \textbf{(E)}\ \text{no finite number}$

$\fbox{B}$

1967 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 22	Followed by Problem 24
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