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1994 AHSME Problems/Problem 9

Revision as of 20:26, 27 June 2014 by TheMaskedMagician (talk | contribs) (Created page with "==Problem== If <math>\angle A</math> is four times <math>\angle B</math>, and the complement of <math>\angle B</math> is four times the complement of <math>\angle A</math>, then ...")
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Problem

If $\angle A$ is four times $\angle B$, and the complement of $\angle B$ is four times the complement of $\angle A$, then $\angle B=$

$\textbf{(A)}\ 10^{\circ} \qquad\textbf{(B)}\ 12^{\circ} \qquad\textbf{(C)}\ 15^{\circ} \qquad\textbf{(D)}\ 18^{\circ} \qquad\textbf{(E)}\ 22.5^{\circ}$

Solution

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