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2014 AMC 12A Problems/Problem 2

Revision as of 17:43, 7 February 2014 by Jack196 (talk | contribs)

Suppose $x$ is the price of an adult ticket. The price of a child ticket would be $\frac{x}{2}$.

$5x + 4(x/2) = 7x = 24.50$ 

               $x = 3.50$

Plug in for 8 adult tickets and 6 child tickets.

$8x + 6(x/2) = 8(3.50) + 3(3.50) = 38.50$

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